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A particle having mass m, charge q, enters a cylindrical region having uniform magnetic field B in the inward direction as shown. If the particle is deviated by 60⁰ as it emerges out of the field, then what is the time spent by it in the field?

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$\frac{2 πm}{qB}$

$\frac{2 πm}{3 qB}$

$\frac{πm}{3 qB}$

It depends on the speed of particle.

answer is C.

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Detailed Solution

Angle rotated in magnetic field = 60⁰

So time taken should be ${\frac{1}{6}}^{t h}$ of time period.

$t = \frac{T}{6} = \frac{1}{6} (\frac{2 πm}{qB}) = \frac{πm}{3 qB}$

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