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A particle having mass m, charge q enters a cylindrical region having uniform magnetic field B in the inward direction as shown. If the particle is deviated by 60º as it emerges out of the field then what is the time spent by it in the field?

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$\frac{2 πm}{qB}$

$\frac{2 πm}{3 qB}$

$\frac{πm}{3 qB}$

It depends on the speed of particle

answer is C.

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Detailed Solution

Particle is deflected by 60º. This means that it is rotated by 60º on its circular path

$t = \frac{T}{6} = \frac{1}{6} \cdot \frac{2 πm}{qB} = \frac{πm}{3 qB}$

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