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A particle in SHM is described by the displacement function $x (t) = Acos (ωt + ϕ)$ . If the initial (t = 0) position of the particle is 1 cm, its initial velocity is p cm $s^{- 1}$ and its angular frequency is π rad s^-1 , then the amplitude of its motion is

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π cm

2 cm

√2 cm

1 cm

answer is C.

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Detailed Solution

$v = ω \sqrt{a^{2} - y^{2}}$

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