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A particle is executing $S . H . M .$ of frequency $300 H z$ and with amplitude $0.1 c m$ . Its maximum velocity will be :

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$0.50 π m / s$

$60 π m / s$

$0.6 π m / s$

$0.05 π m / s$

answer is B.

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Detailed Solution

$V_{m a x} = A ω = \frac{0.1}{100} \times 2 π \times 300 = 0.6 π m / s$

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