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A particle is in simple harmonic motion with amplitude 4 cm and time period 12 sec. The ratio of times taken by it in going from its mean position to 2 cm and from 2 cm to extream position is

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$\frac{1}{3}$

$\frac{1}{4}$

$\frac{1}{2}$

answer is B.

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Detailed Solution

ratio of time taken by the particle for the first half of amplitude to the second half of amplitude in 1:2

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