A particle is moving along a circular path in xy-plane. When it crosses x-axis, it has an acceleration along the path of 1.5 m/s², and is moving with a speed of 10m/s in –ve y-direction. The total acceleration is

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$50 \hat{i} - 1.5 \hat{j} m / s^{2}$

$10 \hat{i} - 1.5 \hat{j} m / s^{2}$

$- 50 \hat{i} - 1.5 \hat{j} m / s^{2}$

$1.5 \hat{i} - 50 \hat{j} m / s^{2}$

answer is C.

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Detailed Solution

$\begin{array}{l} {\bar{a}}_{net} = - a_{c} \hat{i} - a_{t} \hat{j} = \frac{- v^{2}}{r} \hat{i} - a_{t} \hat{j} = - \frac{100}{2} \hat{i} - 1.5 \hat{j} \\ = (- 50 \hat{i} - 1.5 \hat{j}) {ms}^{- 2} \end{array}$

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