A particle is moving along a circular path of radius 5 m with a uniform speed 5m $s^{- 1}$ . What will be the average acceleration when the particle completes half revolution?

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

zero

$10 m / s^{2}$

$\frac{10}{π} m / s^{2}$

$5 π m / s^{2}$

answer is D.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

When it goes to opposite diametrical point, change in velocity is V-(-V)=2V

Time taken to travel half the circle is $\frac{π r}{V}$

Average acceleration = $\frac{2 V^{2}}{π r} = \frac{2 \times 25}{π \times 5} = \frac{10}{π} m / s^{2}$

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test