A particle is moving along a straight line with constant acceleration. At the end of tenth second its velocity become 20 m/s and in tenth second it travels a distance of 10 m. Then the acceleration of the particles will be

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3.8 $m / s^{2}$

$\frac{1}{5}$ $m / s^{2}$

20 $m / s^{2}$

10 $m / s^{2}$

answer is B.

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Detailed Solution

Using v = u+at

$\Rightarrow 20 = u + a \times 10 - - - - (i)$

and $s_{n} = u + \frac{a}{2} (2 n - 1)$

$\Rightarrow 10 = u + \frac{a}{2} (2 \times 10 - 1) - - - - - - (ii)$

on solving (i) and (ii) we get a = 20 $m / s^{2}$

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