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A particle is moving along a straight line with kinetic energy 16 J. If its linear momentum is doubled, kinetic energy of the particle will be

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36 J

48 J

64 J

72 J

answer is C.

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Detailed Solution

$\begin{array}{l} K = \frac{p^{2}}{2 m} \\ \Rightarrow \frac{K'}{K} = {(\frac{p'}{p})}^{2} = {(\frac{2 p}{p})}^{2} \Rightarrow K' = 4 \times 16 J = 64 J \end{array}$

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