Q.

A particle is moving along a vertical circle of radius R=20 m with a constant speed v=31.4   ms1 as shown in Fig. Straight line ABC is horizontal and passes through the centre of the circle.  A shell is fired from point A at the instant when particle is at  C. 
If distance AB is 203 m and shell collides with the particle at  B, ( π=3.14 and  g=10 m/s2)

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a

velocity of projectile will be 30 m/s

b

smallest possible value of the angle θ  of projection, will be 30

c

smallest value of  θ must be  45

d

velocity u of projections should be 20 m/s 

answer is A, B.

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Detailed Solution

Number of revolutions completed must be odd multiples of half
T  =  4  sec,    T. time of light of projectile 
T0=odd2T
24sinθg=(odd)  ×  42    (1)
And   42sin2θg=203    (2)
Solving (1) and (2) and  θ smallest 
We get  tanθ=13                 θ=30
And  4=20 m/s.

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A particle is moving along a vertical circle of radius R=20 m with a constant speed v=31.4   ms−1 as shown in Fig. Straight line ABC is horizontal and passes through the centre of the circle.  A shell is fired from point A at the instant when particle is at  C. If distance AB is 203 m and shell collides with the particle at  B, ( π=3.14 and  g=10 m/s2)