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Q.

A particle is moving in a circular path of radius a with a constant velocity v as shown in the figure. The center of circle is marked by ‘C’. The angular momentum from the origin O can be written as

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a

mvacos⁡2θ

b

mva(1+cos⁡2θ)

c

mva(1+cos⁡θ)

d

mva

answer is A.

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Detailed Solution

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In ∆OPC,

xsin(π-2θ)=asinθ

⇒x=2acosθ

|L→|=mvxsinϕ here ,ϕ=90°-θ

⇒|L→|=mv2acosθcosθ=mva[1+cos2θ]

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