A particle is moving in a circular path of radius 2m with constant angular speed ω. In a time t=π3ω, distance travelled by it and displacement are respectively

θ=wt,distance=Rθ,displacement=2Rsin(θ2)

θ=wt,distance=Rθ,displacement=2Rsin(θ2)

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A particle is moving in a circular path of radius 2m with constant angular speed $ω$ . In a time $t = \frac{π}{3 ω}$ , distance travelled by it and displacement are respectively

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$3 m, \frac{π}{3} m$

$\frac{π}{3} m, 3 m$

$2 m, \frac{2 π}{3} m$

$\frac{2 π}{3} m, 2 m$

answer is D.

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$θ = w t, d i s \tan c e = R θ, d i s p l a c e m e n t = 2 R \sin (\frac{θ}{2})$

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