A particle is moving in a circular path. The acceleration and momentum vectors at an instant of time are $\overrightarrow{\mathrm{a}}=2\widehat{\mathrm{i}}+3\widehat{\mathrm{j}}\mathrm{m}/{\mathrm{s}}^2\text{ and }\overrightarrow{\mathrm{P}}=6\widehat{\mathrm{i}}-4\widehat{\mathrm{j}}\mathrm{kgm}/\mathrm{s}\text{. }$ Then the motion of the particle is

The nature of the motion can be determined only if we know velocity and acceleration as function of time. Here acceleration at an instant is given and not known at other times. 

For uniform circular motion, the dot product of $\overrightarrow{\mathrm{a}}\text{ and }\overrightarrow{\mathrm{P}}$ should be always zero.

So (d) is the correct option.