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A particle is moving in a uniform circular motion on a horizontal surface. Particle position and velocity at time t = 0 are in the shown figure in the coordinate system. Which of the indicated variable in column-I is/are correctly matched by the variable on the vertical axis in the graph(s) shown in column-II for particle’s motion?

Column I Column II
i) X component of velocity p)
ii) Y component of force keeping particle moving in a circle q)
iii) Angular velocity of the particle r)
iv) X – coordinate of the particle s)

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i-q, ii-q, iii-p, iv-s

i-q, ii-q, iii-r, iv-r

i-q, ii-q, iii-r, iv-s

i-p, ii-q, iii-r, iv-s

answer is A.

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Detailed Solution

$v_{x} = - ω A \cos (90^{o} - ω t) \begin{array}{l} v_{x} = - ω A \sin ω t \\ F_{y} - m ω^{2} A \sin ω t \\ x = A \cos ω t \end{array}$

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