Q.

A particle is moving in xy plane. Its velocity and acceleration at a certain instant is given by V=3i^+4j^  m/s and a=5i^+154j^ .Find the rate of change of speed (in ms-2) of particle at that instant___

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answer is 6.

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Detailed Solution

V2=Vx2+Vy2

2VdVdt=2VxdVxdt+2VydVydt

dVdt=Vxax+VyayVx2+Vy2=(3×5)+(4+154)32+42=6ms1

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