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A particle is moving on a circular track of radius 30 cm with a constant speed of 6 m/s. Its acceleration is

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zero

1.2 m/s²

120 m/s²

36 m/s²

answer is B.

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Detailed Solution

$a_{t} = 0, a = a_{n} = \frac{v^{2}}{R} = \frac{{(6)}^{2}}{0.3} = 120 m / s^{2}$

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