A particle is moving parallel to x-axis as shown in the figure such that at all instant the y-component of its position vector is constant and is equal to b. The angular velocities of the particle about origin is

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$\frac{v}{b} \sin θ$

$vb$

$\frac{v}{b}$

$\frac{v}{b} \sin^{2} θ$

answer is A.

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Detailed Solution

$\begin{array}{l} ω_{0} = \frac{velocity perpendicular to line OP}{length of OP} \\ ω_{0} = \frac{vsin θ}{b / \sin θ} = \frac{{vsin}^{2} θ}{b} \end{array}$

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