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Q.

A particle is performing simple harmonic motion having time period 3s is in phase with another particle which is also under-going simple harmonic motion at t=0. The time period of second particle is T (less than 3s). If they are again in the same phase for the third time after 45s, then the value of T is

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a

2.8s

b

2.7s

c

2.5s

d

3.2s

answer is C.

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Detailed Solution

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First time they will meet after 15 mins. 

so first will oscillate 5 times and second will oscillate 6 times

T=15/6=2.5 sec

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