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Q.

A particle is projected from a horizontal plane with a velocity of 82m/s at an angle. At the highest point, its velocity is found to be 8 m/s. Its range will be

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a

6.4 m

b

3.2 m

c

12.8 m

d

4.6 m

answer is C.

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Detailed Solution

The velocity at the highest point =v=v0cos⁡θ0
or 8=82cos⁡θ0 or θ0=45∘
Range =u02sin2θ0g=(82)2sin90∘1064×210=12.8m

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