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A particle is projected from a point O in the horizontal surface OA with speed u and angle of projection $θ$ . It just grazes the plane BC at point P which makes an angle $α$ with the horizontal. The time taken by the projectile to reach P from the instant of projection is

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$\frac{2 usin θ}{gcos α}$

$\frac{usin θ}{gcos α}$

$\frac{usin (θ - α)}{gcos α}$

None of these

answer is C.

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Detailed Solution

Question Image — Tan $\tan α = \frac{u \sin θ - g t}{u \cos θ}$

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