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A particle is projected from a point O on the ground at an angle of $60^{0}$ with velocity 20 m/s. If it strikes the vertical wall at a distance of $x$ from point of projection at angle of $30^{0}$ with the normal to the wall as shown in figure.

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The time taken by particle to strike the wall is $\frac{2}{\sqrt{3}} \sec$

The value of $x$ is $\frac{10}{\sqrt{3}} m$

The value of $x$ is $\frac{20}{\sqrt{3}} m$

The time taken by particle to strike the wall is $\frac{1}{\sqrt{3}} \sec$ .

answer is A, B.

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Detailed Solution

$\tan 30^{0} = \frac{u \sin - g t}{u \cos θ}$ and $s x = 4 \cos θ x t$

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