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A particle is projected from ground at some angle with the horizontal. Let P be the point at maximum height H. At what height above the point P should the particle be aimed to have range equal to maximum height?

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H/2

answer is A.

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Detailed Solution

AC=R/2,PC = H , We have to find h = MP. we know that if H = R, then tan $θ$ =4

Now tan q = $\frac{M C}{A C} = \frac{M P + P C}{A C}$ $\Rightarrow 4 = \frac{h + H}{R / 2}$ $\Rightarrow h = H$

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