A particle is projected from ground with velocity $50 \mathrm{m}/\mathrm{s}$ at $37°$ from horizontal. Find velocity and displacement after 2 s. $\sin 37°=\frac{3}{5}$.

$$\begin{gathered} \sin 37°=\frac{3}{5} \Rightarrow \cos 37°=\frac{4}{5} \\ \mathbf{u}=50·\cos 37°\hat{\mathrm{i}}+50·\sin 37°\hat{\mathrm{j}}=(40\hat{\mathrm{i}}+30\hat{\mathrm{j}}) \mathrm{m}/\mathrm{s} \\ \mathbf{a}=\mathbf{g}=(-10\hat{\mathrm{j}}) \mathrm{m}/{\mathrm{s}}^2 \\ \mathrm{t}=2 \mathrm{s} \end{gathered}$$

$\mathbf{v}=\mathbf{u}+\mathbf{a}\mathrm{t}=40\hat{\mathrm{i}}+30\hat{\mathrm{j}}+\left(-10\hat{\mathrm{j}}\right)\times 2=\left(40\hat{\mathrm{i}}+10\hat{\mathrm{j}}\right) \mathrm{m}/\mathrm{s}$

$\mathbf{s}=\mathbf{u}\mathrm{t}+\frac{1}{2}\mathbf{a}{\mathrm{t}}^2=\left(40\hat{\mathrm{i}}+30\hat{\mathrm{j}}\right)\times 2 + \frac{1}{2}\times (-10\hat{\mathrm{j}})\times 2^2=(80\hat{\mathrm{i}}+40\hat{\mathrm{j}}) \mathrm{m}$