A particle is projected from point O with velocity u in a direction making an angle $α$ with the horizontal. At any instant its position is at point P at right angles to the initial direction of projection. Its velocity at point P is

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$u \sec α$

$u cosec α$

$u \cot α$

$u \tan α$

answer is B.

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Detailed Solution

Horizontal velocity at point $^{'} O^{'} = u \cos α$

Horizontal velocity at Point $^{'} P^{'} = v \sin α$

In projectile motion horizontal component of velocity remains constant throughout the motion

$\begin{array}{l} ∴ v \sin α = u \cos α \\ \Rightarrow v = u \cot α \end{array}$

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