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Q.

A particle is projected from the ground. If the equation of the trajectory is y=x-x2/2, then the time of flight is

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a

2/g

b

22/g

c

3/g

d

4/g

answer is A.

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Detailed Solution

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y=x-12x2y=0 when x=2. Thus, the path of the projectile is as shown in figure. Clearly, the height is maximum when x=1. The maximum height H is given by

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H=1-1212=0.5 Time taken to travel from the highest point to the ground is

t=2Hg=2×1/2g=1gTime of flight=2t=2/g

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A particle is projected from the ground. If the equation of the trajectory is y=x-x2/2, then the time of flight is