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A particle is projected horizontally from a tower with velocity 10 ms^-1. Taking, g = 10 ms^-2. Match
the following two columns at time t = 1 s and mark the correct option from the codes given below.
Column.!
(A) Horizontal component of velocity
(B) Vertical component of velocity
(C) Horizontal displacement
(D) Vertical displacement
Column.!I
(p) 5 SI units
(q) 10 SI unit
(r) 15 SI unit
(s) 20 SI unit

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A B C D

p q s r

A B C D

q q s p

A B C D

q p r s

A B C D

q q q p

answer is D.

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Detailed Solution

In horizontal projectile motion,
Horizontal component of velocity,
$u_{x} = u = 10 {ms}^{- 1}$
Vertical component of velocity,

$u_{y} = g t = 10 \times 1 = 10 {ms}^{- 1}$
Horizontal displacement

$= u \times t = 10 \times (1) = 10 m$

Vertical displacement

$= \frac{1}{2} g t^{2} = \frac{1}{2} \times 10 \times (1)^{2} = 5 m$

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