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Q.

A particle is projected on an inclined plane which is inclined at 300  with the horizontal as shown in figure. Initial speed of the particle is v0 , and inclined plane is sufficiently large. Match the Column- I and Column – II.

Question Image

 

 

 

 

Column-I

Column-II

a)

Range on the inclined plane

p)

v0g3

b)

Velocity of the particle is parallel to the inclined plane at time

q)

2v0g3

c)

Time after which particle strikes the plane is

r)

4v023g

d)

For the given velocity maximum range on the inclined plane

(angle of projection changing)                                       

s)

2v023g

         


 

 

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a

 a-s; b-p; c-q; d-s;

b

a-s; b-q; c-q; d-s;

c

a-s; b-p; c-p; d-s; 

d

a-r; b-p; c-q; d-s;  

answer is D.

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Detailed Solution

Range  R=2V02sin300cos600gcos2300
Time when velocity is parallel to plane  V 0sin300gcos300t=0
  t=V0g3
Time of flight  T=2V0sinαgcosβ
Maximum range  R=v02g(1+sinβ)
 

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