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A particle is projected up with a velocity of $v_{0} = 10 m / s$ at an angle of $θ_{0} = 60^{\circ}$ with horizontal onto an inclined plane. The angle of inclination of the plane is 30^o . The time of flight of the particle till it strikes the plane is (take $g = 10 m / s^{2}$ )

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$\frac{1}{2} s$

$\frac{1}{2 \sqrt{3}} s$

$1 s$

$\frac{2}{\sqrt{3}} s$

answer is C.

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Detailed Solution

$T = \frac{2 u_{y}}{a_{y}} = \frac{2 v_{0} \sin 30^{\circ}}{g \cos 30^{\circ}} = \frac{2}{\sqrt{3}} s$

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