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Q.

A particle is projected upwards with a velocity of 100m/sec at an angle of 600 with the vertical. Find the time in seconds when the particle will move perpendicular to its initial direction, taking g = 10m/sec2

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answer is 20.

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Detailed Solution

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u→.v→.=0            (uxi→+uyj→).(vxi→+vyj→)=0uxvx+uyvy=0ux=100sin60°⇒ux=503m/suy=100cos60°⇒uy=50m/s2500×3+50(50−10×t)=0

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7500+2500=500t10000=500t⇒t=20sec

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