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A particle is taken from point A to point B under the influence of a force field. Now it is taken back from B to A and it is observed that the work done in taking the particle from A to B is not equal to the work done in taking it from B to A. If $W_{nc} and W_{c}$ are the work done by non-conservative and conservative forces present in the system, respectively, $ΔU$ is the change in potential energy and $Δk$ is the change in kinetic energy, then

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$W_{nc} + W_{c} = Δk$

$W_{nc} - ΔU = - Δk$

$W_{c} = - ΔU$

$W_{nc} - ΔU = Δk$

answer is A, B, C.

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Detailed Solution

According to the work-energy theorem for a non-conservative system, we have $W_{c} + W_{nc} = ΔK$

Also, we know that the work done by a conservative force equals the decrease in potential energy, so $W_{c} = - ΔU$

$W_{nc} - ΔU = ΔK$

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