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Q.

A particle is thrown with escape velocity v_e =11.2km/s from the surface of earth. Its velocity at height 3R = 19200 Km is:

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a

9.25 km/s

b

5.6 km/s

c

11.2 km/s

d

4.3 km/s

answer is B.

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Detailed Solution

By using COME
$\begin{array}{l} - \frac{GMm}{R} + \frac{1}{2} {mv}_{e}^{2} = - \frac{GMm}{4 R} + \frac{1}{2} {mv}^{2} \\ \Rightarrow v = 5 .6 km / s \end{array}$

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