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A particle leaves the origin at t = 0 and moves in the positive x-axis direction. Velocity of the particle at any instant is given by $v = u (1 - \frac{t}{t^{'}})$ . If $u = 10 m s^{- 1}$ and $t^{'} = 5 s$ , find the x-coordinate of the particle at an instant of 10 s

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-10m

10 m

20 m

answer is B.

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Detailed Solution

At $t = 10, v = 10 (1 - \frac{10}{5}) = - 10 m s^{- 1}$

Displacement from t = 0 to 10
= Area (from t = 0 to 5) – Area from (t = 5 to 10)
= 0.

Since, particle started from origin, its x-coordinate at t = 10 s is zero

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