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Q.

A particle moved from position r1 →   = 3i^ +2j^-6k^  to position r2→ = 14i^+13j^ + 9 k^ under the action of a force (4i^+j^+3k^) newtons. Find the work done.

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a

0.01 J

b

100 J

c

10 J

d

1 J

answer is B.

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Detailed Solution

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displacement : s→  = r2→ -r1→. Now find W = F→ .s→

 s→= 14i^+13j^+9k^-3i^-2j^+6k^ =11i^+11j^+15k^

W = 44+11+45 = 100 J

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