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Q.

A particle moves along a circle of radius 20π m with constant tangential acceleration. If the velocity of the particle is 80 ms-1  at the end of the second revolution after motion has begun, the tangential acceleration (in m/s2) is:

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a

b

c

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Detailed Solution

Circumference =2πr=2π×20π=40m

Distance travelled in 2 revolutions

=2×40=80m

Initial velocity =u=0

Final velocity v=80m/sec

Applying the formula, v2=u2+2as

(80)2=02+2×a×80⇒a=40m/sec2

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