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Q.

A particle moves along a circle with uniform speed V. When it has moved through an angle $60 º$ , the change in its velocity is

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a

$V$

b

$\sqrt{3} V$

c

$3 V$

d

Zero

answer is D.

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Detailed Solution

$Δ V = 2 V \sin (\frac{θ}{2})$

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