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Q.

A particle moves along a straight line OX. At a time ‘t’ (in second) the position x (in metre) of the particle from O is given by x=40+12t−t3. How far would the particle travel before coming to rest?

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a

24 m

b

56 m

c

16 m

d

40 m

answer is A.

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Detailed Solution

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V=dxdt=12−3t2=0

    t=2 sec

s=x−x0=40+12(2)−23−40=16m

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