A particle moves along y – axis in such a way that its y coordinate changes with time as y = 3 + 5t + 7t2. The initial velocity and acceleration of the particle are respectively.

y=3+5t+7t2velocity dydt=5+14tinitial velocity=5 ms-1acceleration=dvdt=14ms-2

A particle moves along y – axis in such a way that its y coordinate changes with time as y = 3 + 5t + 7t2. The initial velocity and acceleration of the particle are respectively.

y=3+5t+7t2velocity dydt=5+14tinitial velocity=5 ms-1acceleration=dvdt=14ms-2

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A particle moves along y – axis in such a way that its y coordinate changes with time as y = 3 + 5t + 7t². The initial velocity and acceleration of the particle are respectively.

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$- 14 m s^{- 1}, - 5 m s^{- 2}$

$14 m s^{- 1}, - 5 m s^{- 2}$

$14 m s^{- 1}, 5 m s^{- 2}$

$5 m s^{- 1}, 14 m s^{- 2}$

answer is B.

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Detailed Solution

$y = 3 + 5 t + 7 t^{2}$

$velocity \frac{dy}{dt} = 5 + 14 t$

$initial velocity = 5 {ms}^{- 1}$

$acceleration = \frac{dv}{dt} = 14 {ms}^{- 2}$

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A particle moves along y – axis in such a way that its y coordinate changes with time as y = 3 + 5t + 7t2. The initial velocity and acceleration of the particle are respectively.

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A particle moves along y – axis in such a way that its y coordinate changes with time as y = 3 + 5t + 7t². The initial velocity and acceleration of the particle are respectively.