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Q.

A particle moves from a point(-2i^+5j^) to (4j^+3k^)  when a force of (4i^+3j^) N is applied. How much work has been done by the force?

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a

8 J

b

5 J

c

11 J

d

2 J

answer is B.

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Detailed Solution

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Given    r1=2i^+5j^  and r2=4j^+3k^

displacement r2r1=2i^j^+3k^

Since force   F=4i^+3j^
Work done  = Fr=(4i^+3j^)(2i^j^+3k^)=83=5J  

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