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Q.

A particle moves in a circle of radius 1.0 cm with a speed given by v= 2t, where v is in cm/s and t in seconds.

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a

the radial acceleration of the particle at t=1s is 4cm/s2

b

the tangential acceleration at t=1s is 2cm/s2

c

the magnitude of net acceleration at t=1s 135cm/s2

d

the magnitude of net acceleration at t=1s is 25cm/s2

answer is A, B, C.

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Detailed Solution

ar=v2R=(2t)21.0=4t2

At t=1s,ar=4cm/s2

(b) at=dvdt=2cm/s2

(c) a=ar2+at2=(4)2+(2)2

        =25cm/s2

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