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Q.

A particle moves in a circle of radius 10 cm with constant speed and time period π second. Find acceleration of the particle (m/s²)

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a

2 $π$

b

$π$

c

$0.4$

d

$4$

answer is C.

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Detailed Solution

Given, r = 10 cm = $10 \times 10^{- 2} m a n d T = π s$

We know that acceleration a = $r ω^{2} = \frac{4 π^{2}}{T^{2}} r$

= $\frac{4 \times π^{2} \times 10 \times 10^{- 2}}{{(π)}^{2}} = 0.4 m s^{- 2}$

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