A particle moves in a circle of radius 20cm . Its linear speed is given by $v = 2 t$ where t is in second and v in m/s then

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The radial acceleration at ${t=2s is 80m/s}^{2}$

Tangential acceleration at ${t=2s is 2m/s}^{2}$

Net acceleration at t=2s is greater than ${86m/s}^{2}$

Tangential acceleration remains constant in magnitude

answer is A.

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Detailed Solution

$V = 2 t$ and $t = 2 \sec$

$a_{c} = \frac{V^{2}}{r} = \frac{{(2 \times 2)}^{2}}{20 \times 10^{- 2}} = 80 m / \sec^{2}$

$a_{t} = \frac{d v}{d t} = 2 = constant$

$a_{n e t} = \sqrt{a_{c}^{2} + a_{t}^{2}} = \sqrt{80^{2} + 2^{2}}$ = $\sqrt{6400 + 4} = \sqrt{6404} ≃ 80 m / s^{2}$

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