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Q.

A particle moves in a straight line with a uniform acceleration $a .$ Initial velocity of the particle is zero. Find the average velocity of the particle in first $' s'$ distance.

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a

$\sqrt{\frac{a s}{5}}$

b

$\sqrt{\frac{a s}{3}}$

c

$\sqrt{\frac{a s}{4}}$

d

$\sqrt{\frac{a s}{2}}$

answer is D.

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Detailed Solution

$∵ s = \frac{1}{2} a t^{2} ∴ \frac{s^{2}}{t^{2}} = \frac{1}{2} a s A v e r a g e v e l o c i t y = \frac{s}{t} = \sqrt{\frac{a s}{2}}$

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