A particle moves in a straight line with the velocity as shown in figure. At $t = 0, x = - 16 m$ .The maximum value of the position coordinate of the particle is ________.

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answer is 54.

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Detailed Solution

Max value of position coordinate
$\begin{array}{l} = - 16 + [2 \times 10 + \frac{2 + 6}{2} \times (18 - 10) + \frac{1 \times 6}{2} (24 - 18)] \\ = 54 m \end{array}$

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