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Q.

A particle moves in the X – Y plane under the influence of a force such that its linear momentum is  P(t)=A[i^cos(kt)j^sin(kt)] where A and k are constants. The angle between the force and momentum is

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a

45°

b

90°

c

30°

d

answer is D.

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Detailed Solution

P=Ai^cos(kt)j^sin(kt)

F=dPdt=ddt=A[i^cos(kt)j^sin(kt)]=Ak[i^sinktj^cos(kt)]FP

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