A particle moves in the x-y plane according to the equation; r→=(i^+j^)(Asinωt+Bcosωt). Motion of the particle is

The particle will move along the line y=x.cosωt+sinωt=2sinωt+45o.So the given motion will be SHM.

The particle will move along the line y=x.cosωt+sinωt=2sinωt+45o.So the given motion will be SHM.

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A particle moves in the x-y plane according to the equation; $\vec{r} = (\hat{i} + \hat{j}) (A \sin ω t + B \cos ω t) .$ Motion of the particle is

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SHM

Periodic

Along a straight line

All of the above

answer is D.

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The particle will move along the line y=x.

$cosωt + sinωt = \sqrt{2} \sin (ωt + 45^{o})$ .

So the given motion will be SHM.

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