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Q.

A particle moves in the x-y plane under the influence of a force such that its linear momentum is p(t)=A[i^cos(kt)j^sin(kt)] , where A and k are constants. Angle between the force and the momentum is:

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a

b

30°

c

45°

d

90°

answer is D.

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Detailed Solution

F=dpdt=Ak[i^sinktj^coskt]
Let angle between F and p be θ , then
cosθ=FpFp
But Fp=0 so cosθ=0
θ=90

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