Q.

A particle moves in X-Y plane with constant acceleration 'a’ directed along negative Y axis. The equation of motion of the particle has the form y=pxqx2 where p, q are positive constants. The velocity of the particle at the origin of coordinates is found to be a(n+p2)2q.  Find the value of n

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answer is 1.

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Detailed Solution

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y=tanθxa2u2cos2θx2   compare   y=pxqx2   q=a2u2cos2θ.

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