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A particle moves perpendicularly towards a plane mirror with a constant speed of 4 $c m / s$ .

What is the speed of the image observed by an observer moving with 2 $c m / s$ along the same direction. Mirror is also moving with a speed of 10 $c m / s$ in the opposite direction. (All speeds are with respect to ground frame of reference)

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4 $c m / s$

12 $c m / s$

14 $c m / s$

26 $c m / s$

answer is D.

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Detailed Solution

$v_{P M} = 14 c m / s$ towards right

$v_{I M} = 14 c m / s$ towards left

$V_{o / M} = (10 + 2) c m / s = 12 c m / s$ towards right.

So velocity of the image relative to the observer , $V_{\frac{I}{o}} = (14 + 12) m / s$ = $24 c m / s$ towards left

$v_{I O} = 26 c m / s$ towards left

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