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Q.

A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is

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a

$\frac{2 {πr}^{2}}{T}$

b

$\frac{2 πν}{T}$

c

$\frac{2 πr}{T}$

d

$\frac{2 {πν}^{2}}{T}$

answer is A.

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Detailed Solution

Acceleration = $ω^{2} r = \frac{v^{2}}{r} = ω v = \frac{2 π}{T} v$

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