A particle moves with simple harmonic motion in a straight line. In first 3 s after starting from rest, it travels a distance of 4 cm, and in next 3 s it travels 8 cm, in the same direction. If A is amplitude and T is time period of the SHM, then

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A = 8 cm

T = 6 s

A = 6 cm

T = 12 s

answer is A.

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Detailed Solution

The particle executing SHM moves A/2 distance in T/6 seconds (starting from extreme position or starting from rest, and moves distance A in next T/6 seconds. Hence from the given data,
A/2=4 cm⇒A=4 cm and T/6=3 s⇒T=18 s

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